Question

A boat is traveling at an initial velocity of 2.7 meters per second in the positive direction. It accelerates at a rate of 0.15 meters per second squared for 12 seconds. What is the final velocity of the boat? ​

Answer 1

`\boxed {\boxed {\sf 4.5 \ m/s \ in \ the \ positive \ direction}}`

Step-by-step explanation:

We are asked to find the final velocity of the boat.

We are given the initial velocity, acceleration, and time. Therefore, we will use the following kinematic equation.

`v_f= v_i + at`

The initial velocity is 2.7 meters per second. The acceleration is 0.15 meters per second squared. The time is 12 seconds.

• 
  `v_i`= 2.7 m/s
• a= 0.15 m/s²
• t= 12 s

Substitute the values into the formula.

`v_f = 2.7 \ m/s + (0.15 \ m/s^2)(12 \ s)`

Multiply the numbers in parentheses.

`v_f= 2.7 \ m/s + (0.15 \ m/s/s * 12 \ s)`

`v_f = 2.7 \ m/s + (0.15 \ m/s *12)`

`\v_f=2.7 \ m/s + (1.8 \ m/s)`
`v_f=2.7 \ m/s + (1.8 \ m/s)`

Add.

`v_f=4.5 \ m/s`

The final velocity of the boat is 4.5 meters per second in the positive direction.