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A hot air balloon is filled with 1.19 x 106 L of an ideal gas on a cool morning (11 °C). The air is heated to 113 °C. What is the volume of the air in the balloon after it is heated? Assume that none of
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A hot air balloon is filled with 1.19 x 106 L of an ideal gas on a cool morning (11 °C). The air is heated to 113 °C. What is the

volume of the air in the balloon after it is heated? Assume that none of the gas escapes from the balloon.

User Navin Gupta
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1 Answer

6 votes

Answer:

using the Charles law

v1/t1= v2/t2

Step-by-step explanation:

1.19* 10^6/11+273=v2/113+273

1.19*10^6/284=v2/386

v2= 1.19*10^6/284/386

v2= 10.89L

User Azizbekian
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