Answer:
9.18 L
Step-by-step explanation:
When aluminum is placed in concentrated hydrochloric acid, hydrogen gas is produced. 2Al(s)+6HCl(aq)⟶2AlCl3(aq)+3H2(g) What volume of H2(g) is produced when 7.40 g Al(s) reacts at STP?
first write, then balance the equation
Al + HCl-------------> AlCl3 + H2
2Al + 6HCl-----------> 2AlCl3 + 3H2 2 MOLE
2 moles of Al produce 3 moles of H2
Al is 7.4/27 =
0.27 moles of Al.
this will produce
0.27 X 3/2 moles of H2 =
0.41 moles of H2
PV =nRT
for STP, P = 1 atm, T = 273.2, R IS 0.082
V= (0.41) X 0.082 X 273,2/1 = 9.18 L
CHECK 1 mole of gas at STP has a volume of 22.4 L
0.41 moles then has a volume of 00.41 X 22.4L = 9.,18 L