By the product and chain rules,
f'(x) = g(h(x)) + x g'(h(x)) h'(x)
Then
f'(3) = g(h(3)) + 3 g'(h(3)) h'(3)
f'(3) = g(4) + 3 g'(4) (-2)
f'(3) = g(4) - 6 g'(4)
f'(3) = 2 - 6(3)
f'(3) = -16
5.8m questions
7.6m answers