Question

The chemical equation below shows the reaction between carbon dioxide (CO2) and lithium hydroxide (LiOH). CO2 2LiOH Right arrow. Li2CO3 H2O The molar mass CO2 is 44. 01 g/mol. How many moles of LiOH are needed to react completely with 25. 5 g of CO2? 0. 290 moles 0. 579 moles 1. 16 moles 1. 73 moles.

Answer 1

C

Step-by-step explanation:

The reaction between carbon dioxide and lithium hydroxide can be represented by the equation:

`\displaystyle \text{CO$_2$} + 2\text{LiOH} \longrightarrow \text{Li$_2$CO$_3$}+ \text{H$_2$O}`

We want to determine the amount of moles of LiOH needed to react completely with 25.5 g of CO₂.

Determine the number of moles of CO₂ in 25.5 g of CO₂:

`\displaystyle 25.5\text{ g CO$_2$} \cdot \frac{1\text{ mol CO$_2$}}{44.01\text{ g CO$_2$}} = 0.579\text{ mol CO$_2$}`

Use stoichiometry to determine the amount of LiOH necessary. CO₂ and LiOH are in a 1:2 ratio. That is, for every one mole of CO₂ that reacts, two moles of LiOH must also react.

`\displaystyle 0.579\text{ mol CO$_2$} \cdot \frac{2\text{ mol LiOH}}{1\text{ mol CO$_2$}} = 1.16\text{ mol LiOH}`

In conclusion, our answer is C.