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(n^5)/(n-6) * (n^2-6)/(n^8)

User Molarro
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1 Answer

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Explanation:

Dod you mean


= \frac{ {n}^(5) }{ {n}^( - 2) } * \frac{ {n}^(2 - 6) }{ {n}^(8) }


= {n}^(5 - ( - 2)) * {n}^(2 - 6 - 8)


= {n}^(7) * {n}^( - 12)


= {n}^(7 + ( - 12))


= {n}^( - 5) = \frac{1}{ {n}^(5) }

User Mitaka
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