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Heya! ~


\underline{ \underline{ \tt{QUESTION}}} :
- If the line y = mx + c passes through the point of intersection of the lines x - 2y = -1 and y = 2 and is perpendicular to the line y = 4x + 8 , then find the values of m and c.
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User Obsidian
by
3.2k points

2 Answers

2 votes

☆Answer :

  • m = -¼
  • c = 2¾

Answer in the picture.

Heya! ~ \underline{ \underline{ \tt{QUESTION}}} : - If the line y = mx + c passes-example-1
User Mcheah
by
3.6k points
6 votes

Answer:


m = - (1)/(4)


c = 2 (3)/(4)

Explanation:

Let's start by finding the point of intersection of the lines x -2y= -1 and y= 2.

x -2y= -1 -----(1)

y= 2 -----(2)

Substitute (2) into (1):

x -2(2)= -1

x -4= -1

x= 4 -1

x= 3

Thus, the point of intersection is (3, 2).

y= 4x +8

Slope= 4

The product of the slopes of perpendicular lines is -1.

4m= -1

m= -¼

y= -¼x +c

Since the line passes through (3, 2), we can substitute this coordinates into the equation to find the value of c.

When x= 3, y= 2,


2 = - (1)/(4) (3) + c


c = 2 + (3)/(4)


c = 2 (3)/(4)

User KumarM
by
3.7k points