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Consider functions f and g

f(x)=(1=2)^×+1 g(x)= log(x - 1) +1 Using three iterations of successive approximation, what is the approximate solution where f(x) g(x)? Use the graph as a starting point.​

Consider functions f and g f(x)=(1=2)^×+1 g(x)= log(x - 1) +1 Using three iterations-example-1

2 Answers

2 votes

Answer:

x=39/16

Explanation:

I looked it up. Here's the source's explanation;

f(x)=(1/2)^x+1

g(x)=log(x-1)+1


f(x)=g(x)

(1/2)^x +1=log(x-1)+1

(1/2)^x=log(x-1)
2^(-x)=log (x-1)
x=2.5018
x=39/16

User Dnivra
by
8.5k points
7 votes

Answer:

41/16

Explanation:

took the text and got 100, good luck besties

User Carmina
by
8.3k points
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