Question

10.

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

–x + 5y = 14; (–5, –2)

A. y = 5^x – 27

B. y = -1/5x – 27

C. y = -1/5x – 15

D. y = -5^x – 27

Answer 1

D. y = -5^x – 27

Explanation:

Find the negative reciprocal of the slope of the original line and use the point-slope formula y − y 1 = m ( x − x 1 ) to find the line perpendicular to − x + 5 y = 14 .

y = − 5 x − 27 PERPENDICULAAR

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Find the slope of the original line and use the point-slope formula y − y 1 = m ( x − x 1 ) to find the line parallel to − x + 5 y = 14 .

y = 1 /5 x − 1 PARALLEL