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4 votes
Having problems with this question help needed

Having problems with this question help needed-example-1
User Leotsarev
by
4.4k points

2 Answers

5 votes

Answer:

  • No

Explanation:

We will substitute 3 for the value of x in the equation.


{ \longrightarrow \sf \qquad 3x-5=4+2x }


{ \longrightarrow \sf \qquad 3( - 3)-5=4+2( - 3) }


{ \longrightarrow \sf \qquad - 9-5=4+( - 6) }


{ \longrightarrow \sf \qquad -14=4 - 6}


{ \longrightarrow \sf \qquad -14= - 2}

We can see that,


{ \longrightarrow \sf \qquad L.H.S ≠ R.H.S}

Therefore,


{ \longrightarrow \sf \qquad 3 \: is \: not \: a \: solution \:of \: equation \: ( 3x-5=4+2x) }

User Ben Carlson
by
4.7k points
4 votes

Answer:

-3 is not a solution

Explanation:

Subtstitute the possible solution into the equation and see if it is true

3x -5 = 4+2x

3(-3) -5 = 4+2(-3)

-9-5 = 4-6

-14 = -2

This is not true so -3 is not a solution

User Dross
by
5.0k points