Question

7. A parachutist jumps from a plane and reaches a terminal velocity of 45.0 m/s. Once he

opens his parachute, he slows to 5.0 m/s it a span of 20 s. What was his rate of
deceleration?

Answer 1

(45. 0 m/s) - (5.0 m/s) ÷ 20

40 m/s ÷ 20 s = 2 meter second minus 2.

I am sry if my ans is wrong