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What is the equation of the line that passes through the point (5,-2) and has a slope of 6/5?

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Answer:

y=6/5x-8

Explanation:

Hi there!

We want to find the equation of the line that passes through (5, -2) and has the slope of 6/5

We can write the equation of the line in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept.

Since we are already given the slope of the line, we can immediately plug it into the equation:

y=6/5x+b

Now we need to find b

Since the equation passes through the point (5, -2), we can use it to solve for b

Substitute 5 as x and -2 as y:

-2=6/5(5)+b

Multiply

-2=6+b

Subtract 6 from both sides

-8=b

Substitute -8 as b.

y=6/5x-8

Hope this helps!

User MayuriXx
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