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(sinx)(tanx+cotx)
I know it =secx but I don't know how to get to it​

User Kylo
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1 Answer

4 votes

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Step-by-step explanation:

It is often useful to put everything in terms of sine and cosine.

sin(x)·(tan(x) +cot(x))

= sin(x)·(sin(x)/cos(x) + cos(x)/sin(x))

= sin(x)²/cos(x) +cos(x) . . . . . . use the distributive property*

= (sin(x)² +cos(x)²)/cos(x) . . . . . combine terms over a common denominator

= 1/cos(x)

= sec(x)

_____

* The expression inside parentheses could have been combined to ...

(sin(x)² +cos(x)²)/(sin(x)·cos(x))

Then the sin/sin factors cancel, leaving the expression on line 4.

User Malisa
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