Question

What is the solution to logs(10x-1)= logs(9x+7)?

6
X=
19
X
8
19
X-7
OX-8
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Answer 1

Explanation:

`\log_(5)(10x - 1) = \log_(5)(9x + 7)`

`10x - 1 = 9x + 7`

`10x - 9x = 7 + 1`

`x = 8`

`\:`

Option → D