Question

For the following quadratic function, find the axis of symmetry, the vertex and the y-intercept. y = x^2 + 8x + 12

A) axis of symmetry: x = 4; vertex: (4,60); y-intercept: 12
B) axis of symmetry: x = -8; vertex (-8,12); y-intercept: -8
C) axis of symmetry: x = -4; vertex: (-4,-4); y-intercept: 12
D) axis of symmetry: x = 8; vertex: (8,140); y-intercept: 8

Answer 1

C

Explanation:

-4 is the x-axis on the vertex and 12 is the number where the graph crosses the y-axis