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Can anyone quickly solve this trig problem, thank you!

Can anyone quickly solve this trig problem, thank you!-example-1
User Tanvi B
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7.4k points

2 Answers

1 vote

Answer:

Explanation:

a) A = (28 - 14) / 2 = 7

b) T = 2(11½ - 6½) = 10

c) P = (6½ - T/4, 28 - A) = (4, 21)

d) general form y = Asin(ωx + φ) + d

We have already found amplitude A = 7

the upward displacement from the x axis is 21

The portion in parenthesis will be in radians. The cycle repeats every 10 x units so ω = 2πx/10 = 0.2πx

To find φ, which is 4/10 of a cycle behind the upward tracing zero point, we subtract 2π(4/10) = 0.8π

y = 7sin(0.2πx - 0.8π) + 21

y = 7sin(π(0.2x - 0.8)) + 21

e) The easiest "difference" we can make is to change φ

Because the pattern repeats, 4/10 of a cycle backward is the same as 6/10 of a cycle forward. 6/10(2π) = 1.2π

y = 7sin(π(0.2x + 1.2)) + 21

We could also change it to a cosine function which would also change our option for φ by π/2

User Zory
by
8.6k points
1 vote

Answer:

Explanation:

User Jeff Baranski
by
8.7k points

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