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2 vertical buildings are 42 metres apart and the shorter building is 135m high. The angle of elevation from the top of the shorter building to the top of the taller building is 60 degrees. Find the height of the taller building to the nearest metre.

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Answer:

Explanation:

base=42 m

height=h=?

base angle θ=60°

tan 60=h/42

h=42tan 60=42√3≈72.75 m

height of taller building=135+42√3 m≈135+72.75≈207.75 m≈208 m

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