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Need help with geometric series'!
Please include a step by step explanation.

Need help with geometric series'! Please include a step by step explanation.-example-1
User Tao Nhu
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13 votes

Answer:


- 13107

Explanation:

We would like to evaluate the following Geometric Series ,


\displaystyle\longrightarrow \sum _(n=1)^8 (-4)^(n-1 )

In a geometric series, a common number is multiplied to the previous term in order to find the next term . And that common number is called common ratio (r) .

As we know that ,


\displaystyle\longrightarrow \sum_(x = 1)^n f(x) = f(1) + f(2) + \dots + f(n)

So , we can write the series as ,


\displaystyle\longrightarrow (-4)^(1-1)+(-4)^(2-1)+\dots +(-4)^(8-1)

Simplify,


\displaystyle\longrightarrow (-4)^0 + (-4)^1+(-4)^2+\dots +(-4)^7

We can find the common ratio by dividing and successive term by its preceding term , as ;


\displaystyle\longrightarrow r =(-4)/(1)=-4

Again , here ;

  • First term = a =
    (-4)^0=1
  • Common ratio =
    -4
  • number of terms (n) = 8

And we can find the sum of geometric series using the formula , ( this is used when the value of r is less than 1 , here it is -4 ) .


\displaystyle\longrightarrow \Bigg[ Sum = (a(1-r^n))/(1-r)\Bigg]

  • where the symbols have their usual meaning.

On substituting the respective values, we have;


\displaystyle \longrightarrow\rm{ Sum }=\frac{ 1\{1-(-4)^8\}}{1-(-4)}\\

Simplify ,


\displaystyle\longrightarrow \rm{Sum} = (1-65536)/(1+4)\\


\displaystyle\longrightarrow \rm{Sum} = (-65535)/(5)

Simplify by dividing ,


\displaystyle\longrightarrow \underline{\underline{ \rm{Sum} = -13107}}

And we are done !

User Pallupz
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