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Use nCk =
(n!)/(k! (n-k))


How many different combos of 6 children can fit on 4 chairs?


[?] ways

User Ssank
by
7.9k points

1 Answer

6 votes

Answer:

15 ways

Explanation:


(6!)/(4!(6-4)!)=(6!)/(4!2!)=15

User John Jelinek
by
8.1k points
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