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Write the equation of a line that is perpendicular to the line y = 2x + 3 and

passes through the point (2, 3).

1 Answer

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Answer:

y = -1/2x +4

Explanation:

The given equation is in slope-intercept form, so you can see the slope of the given line is 2 (the coefficient of x). The slope of the perpendicular line will be the opposite reciprocal of that, -1/2. The y-intercept (b) of the reciprocal line can be found from ...

b = y -mx

b = 3 -(-1/2)(2) = 4

Then the slope-intercept form equation for the perpendicular line through (2, 3) is ...

y = mx +b . . . . . . . . where m is the slope and b is the y-intercept

y = -1/2x +4

Write the equation of a line that is perpendicular to the line y = 2x + 3 and passes-example-1
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