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I need help finding how this would work with numerical relationships x^3-3x^2+3xy^2-y^3=(x-y)^3 Thx in advance
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I need help finding how this would work with numerical relationships x^3-3x^2+3xy^2-y^3=(x-y)^3

Thx in advance

User Yamila
by
7.2k points

1 Answer

2 votes

Answer:

y=mx+b

Explanation:

User Indika K
by
7.3k points
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