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Pls help 19 a. 100 pts

Pls help 19 a. 100 pts-example-1
User TKV
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2 Answers

4 votes

Answer:

$30 rental with $720 revenue per day

Explanation:

28 kayaks rented each for $25 per day.

Each $5 increase in price results in loss of 4 rentals.

It is:

4/5 = 0.8 rentals loss per $1 increase

The revenue is:

R = P*N, where P - rental price, N- number of kayaks rented

Let the change be x, then the revenue is:

R = (25 + x)(28 - 0.8x) = 700 + 8x - 0.8x²

This is a quadratic function. It has its maximum at vertex, which is determined as x = - b/2a.

The vertex is:

x = - 8 / (-0.8*2) = 5

The maximum revenue at this value is:

R = (25 + 5)(28 - 4) = 30*24 = 720

User Memory Of A Dream
by
8.1k points
4 votes

Answer:

  • $30 rental with $720 revenue per day

Explanation:

28 kayaks rented each for $25 per day.

Each $5 increase in price results in loss of 4 rentals.

It is:

  • 4/5 = 0.8 rentals loss per $1 increase

The revenue is:

  • R = P*N, where P - rental price, N- number of kayaks rented

Let the change be x, then the revenue is:

  • R = (25 + x)(28 - 0.8x) = 700 + 8x - 0.8x²

This is a quadratic function. It has its maximum at vertex, which is determined as x = - b/2a.

The vertex is:

  • x = - 8 / (-0.8*2) = 5

The maximum revenue at this value is:

  • R = (25 + 5)(28 - 4) = 30*24 = 720
User Nagesh Susarla
by
8.7k points

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