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3 votes
Determine the slope and y-intercept of a line that passes through the points (-2, 6) and

(4, -3).

2 Answers

1 vote

Answer:

Y = 3

Explanation:

Y = -3/2x +3

Y = -3/2 × 0 + 3

Y = 3

User David Barrows
by
7.9k points
3 votes

Answer:


y = (-3)/(2)x + 3

Explanation:

Step 1 - Calculate slope first via the equation:


(y2 - y1)/(x2 - x1)

Where x1 and y1 are the coordinates of the first set whereas x2 and y2 are the second set. Plug the variables in:


(6 - (-3))/(-2 - 4) \\(6 + 3 ))/(-2 - 4) \\(9)/(-6)

Which simplifies to:


(3)/(-2)

Now, in the line equation form we know x:

y = mx + c

y =
(3)/(-2)x + c

Step 2 - Calculate y intercept

Plug the variables of one point into the above equation:

y =
(3)/(-2)x + c


6 = (3)/(-2)(-2) + c


6 = (3)/(-2)(-2) + c \\6 = 3 + c\\6 - 3 = c\\c = 3\\

Meaning that the full line equation is:


y = (-3)/(2)x + 3

Hope this helps!

User Zanbri
by
7.5k points

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