162k views
5 votes
Solve for b

B=??????

Solve for b B=??????-example-1
User Mark Byers
by
6.9k points

1 Answer

3 votes

Answer:


(b-7)/(b+1)=(b-10)/(b+4)


\left(b-7\right)\left(b+4\right)=\left(b+1\right)\left(b-10\right)


\left(b-7\right)\left(b+4\right)=b^2-3b-28


\left(b+1\right)\left(b-10\right)=b^2-9b-10


b^2-3b-28=b^2-9b-10


b^2-3b-28+28=b^2-9b-10+28


b^2-3b=b^2-9b+18


b^2-3b-\left(b^2-9b\right)=b^2-9b+18-\left(b^2-9b\right)


6b=18


(6b)/(6)=(18)/(6)


b=3