Answer:
20 m N = 20 j
7.5 m E = 7.5 i
S = 7.5 i + 20 j single displacement vector
tan theta = 7.5 / 29 = 2,67
theta = 69.4 deg North of East
(7.5^2 + 20^2) )1/2 = 21.4 m displacement of single vector
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