Question

Find f(b-2) if f(x) = x^2-6x+1

Answer 1

b^2-10b+ 17

Explanation:

f(b-2) = (b-2)^2-6(b-2)+ 1

= b^2 + 4 - 4b -6b + 12 +1

=b^2-10b+ 17

Answer 2

`▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪`

The equivalent expression is ~

• 
  `f(b - 2) = {b}^(2) - 10b + 17`

`\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}`

Let's evaluate f(b - 2) ~

• 
  `f(x) = {x}^(2) - 6x + 1`

• 
  `f(b - 2) = (b - 2) {}^(2) -6 (b - 2) + 1`

• 
  `\mathcal{ {f(b - 2) = {b}^(2) + 2 {}^(2) - (2 * b * 2) - 6b + 12}}`

• 
  `f(b - 2) = {b}^(2) + 4 - 4b - 6b + 12 + 1`

• 
  `f(b - 2) = {b}^(2) - 10b + 17`