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Answer C, D, E, and F please

Answer C, D, E, and F please-example-1
User Arun T
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1 Answer

1 vote

Answer:

Explanation:

(the second answer for b is .416)

c.) P(11.5<x<13.5) = p(x<13.5)-p(x<11.5)

p(x<13.5)= (13.5-12)/1.5= 1= 0.8413

p(x<11.5) = (11.5-12)/1.5= -1/3= 1-0.6293= .3707

.8413-.3707=.4706

d.) standard deviation of the average is .416025147 which i will refer to as s (the mean of the average is just the mean)

p(11.5<x<13.5)= p(x<13.5)-p(x<11.5)

p(x<13.5)= (13.5-12)/s= 3.61= 0.9998

p(x<11.5)= (11.5-12)/s = -1.2 = 1-0.8849= .1151

.9998-.1151=.8847

e.) yeah i think so

Q1= -.675=(x-12)/s = 11.72

Q3= .675=(x-12)/s= 12.28

IQR= Q3-Q1= 12.28-11.72= .56

User Andy Hopper
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3.0k points