Question

Logariths, please help​

Answer 1

{ - 2 , 8 }

Explanation:

`log_(4)` ( x² - 6x ) = 2

4² = ( x² - 6x )

x² - 6x - 16 = 0

- 6 = - 8 + 2

- 16 = - 8 * 2

( x - 8 )( x + 2 ) = 0 ⇒
`x_(1)` = - 2 ,
`x_(2)` = 8

{ - 2 , 8 }