Answer: False. The number
is not a multiple of 10
========================================================
Step-by-step explanation:
Let's look at a fairly small table of powers of 3 and 7. Check out the diagram below.
Notice that the units digits for each power involve the items from this set: {1,3,7,9}.
Furthermore, note that in each blue row we have the units digits add to 3+7 = 10 or 7+3 = 10. In order to be a multiple of 10, we need to have 0 as the units digit. Eg: 90 is a multiple of 0 for this reason.
So
is one multiple of 10
And so is

and so on. As the table shows, we have
as some multiple of 10 as long as n is an odd positive integer. This contradicts the fact that 40 is an even integer for
. So there's no way that this expression (whatever the massive number happens to be) is a multiple of 10. The units digit for this sum is not zero.
----------------------
You can use modular arithmetic as an alternative pathway to show that the given number isn't a multiple of 10

This shows that the units digit of
is 1
Also,

which looks very similar to the steps of
. This produces the same units digit. The two units digits add to 1+1 = 2, which is not zero and this is sufficient proof to show that
is not a multiple of 10.
Going back to the table below, we see that the units digit of 1 show ups for both 3^n and 7^n whenever n is a multiple of 4. This applies to 40 because 40 = 4*10.