A ball is thrown vertically up from the edge of a cliff with a speed of 8 m/s, how high is the cliff, if it took 16.4 s for the ball to reach the ground?

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asked Nov 26, 2022 43.0k views

5 votes

A ball is thrown vertically up from the edge of a cliff with a speed of 8 m/s, how high is

the cliff, if it took 16.4 s for the ball to reach the ground?

Physics
college

Gallamine asked

by Gallamine

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1 Answer

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Step-by-step explanation:

s=d/t

d=s×t

d=8×16.4

d=131.2

distance is 131.2m.

Gabor Lengyel answered Dec 2, 2022

by Gabor Lengyel

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