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A ball is thrown vertically up from the edge of a cliff with a speed of 8 m/s, how high is the cliff, if it took 16.4 s for the ball to reach the ground?
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A ball is thrown vertically up from the edge of a cliff with a speed of 8 m/s, how high is

the cliff, if it took 16.4 s for the ball to reach the ground?

User Gallamine
by
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1 Answer

2 votes

Step-by-step explanation:

s=d/t

d=s×t

d=8×16.4

d=131.2

distance is 131.2m.

User Gabor Lengyel
by
4.0k points
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