Answer:
see explanation
Explanation:
(1)
a + 3b = 5 ( subtract 3b from both sides )
a = 5 - 3b → (1)
3a + 2b = 8 → (2)
Substitute a = 5 - 3b into (2)
3(5 - 3b) + 2b = 8 ← distribute and simplify left side
15 - 9b + 2b = 8
15 - 7b = 8 ( subtract 15 from both sides )
- 7b = - 7 ( divide both sides by - 7 )
b = 1
Substitute b = 1 into (1)
a = 5 - 3(1) = 5 - 3 = 2
Then a = 2 and b = 1
(2)
3m - 4n = - 14 → (1)
2m + 2n = 14 → (2)
Multiplying (2) by 2 and adding to (1) will eliminate the n- term
4m + 4n = 28 → (3)
Add (1) and (3) term by term to eliminate n
7m + 0 = 14
7m = 14 ( divide both sides by 7 )
m = 2
Substitute m = 2 into either of the 2 equations and solve for n
Substituting into (2)
2(2) + 2n = 14
4 + 2n = 14 ( subtract 4 from both sides )
2n = 10 ( divide both sides by 2 )
n = 5
Then m = 2 and n = 5