Question

PLEASE HELP ME WITH THIS QUESTION PLEASE
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Answer 1

height ≈ 178.3 m

Explanation:

∠ ACB = 27° ( alternate angles )

Using the tangent ratio in the right triangle

tan27° =
`(opposite)/(adjacent)` =
`(AB)/(BC)` =
`(AB)/(350)` ( multiply both sides by 350 )

350 × tan27° = AB , then

AB ≈ 178.3 ( to 1 dec. place )

The height of the plane is approximately 178.3 m