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When 0.06 moles of lead(II) nitrate are dis- solved in enough water to make 656 mililiters of solution, what is the molar concentration of nitrate ions?
Answer in units of M.

User TigrisC
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1 Answer

4 votes

Answer:

M=0.09 mol/L

Step-by-step explanation:

M=mol/volume

M=0.06 mol/0.656 L(convert 656 ml to L by ÷ by 1000)

M=0.09 mol/L

User Dmeglio
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3.5k points