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A certain source emits radiation of wavelength 525 nm, What is the energy, in j.

User Astri
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1 Answer

6 votes

Answer:


3.7837 * {10}^( - 19) j

Step-by-step explanation:


e = (hc)/( \lambda) \\ where \: h \: = plancks \: constant \\ and \: c = speed \: of \: light

Planck constant value: h =
6.62606957 * {10}^( - 34) j \: s\:

speed of light constant: c =
299,792,458 (m)/( s)


hc = 6.62606957 * {10}^( - 34) j \: s\: \: * \\ 299792458 = 1.98645 * {10}^( - 25) j \: m

Divide the wavelength in nanometers by 10^9 to calculate the value in meters.


\frac{525}{ {10}^(9) } = 5.25 * {10}^( - 7) m


e = (hc)/( \lambda) \\ = \frac{1.98645 * {10}^( - 25) j \: m}{ 5.25 * {10}^( - 7) m}


= 3.7837 * {10}^( - 19) j

User Sachin Tyagi
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