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Rationalisie the denominator of: 4√3/2-√2​

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Answer:


\longmapsto4 √(3) + 2 √(6) .

Explanation:


\sf{(4√(3))/(2 - √(2))}

By Rationalizing the denominator:-


= \sf{(4√(3))/(2 - √(2)) * (2 + √(2))/(2 + √(2))}


= \sf{(4√(3)(2 + √(2)))/((2)^2 - (√(2))^2)}


= \sf{(4√(3)(2 + √(2)))/(4 - 2)}


= \sf{(4√(3)(2 + √(2)))/(2)}


= \sf{\frac{\\ot{4}√(3)(2 + √(2))}{\\ot{2}}}


= \sf{2√(3)(2 + √(2))}


= \sf{4√(3) + 2√(6)}


\therefore \sf{(4√(3))/(2 - √(2)) = 4√(3) + 2√(6)}

User Jayant Patil
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