Question 1

Rationalisie the denominator of: 3/√5+√2

Question 2

Answer:

$\longmapsto \: √(5) - √(2.)$

Explanation:

$\sf{(3)/(√(5) + √(2))}$

By rationalizing the denominator,

$=\sf{(3)/(√(5) + √(2)) * (√(5) - √(2))/(√(5) - √(2))}$

$=\sf{(3(√(5) - √(2)))/((√(5) + √(2))(√(5) - √(2)))}$

Applying the identity in the denominator:-

$\boxed{\underline{\red{\rm{(a + b)(a - b) = a^2 - b^2}}}}$

$=\sf{(3(√(5) - √(2)))/((√(5))^2 - (√(2))^2)}$

$=\sf{(3(√(5) - √(2)))/(5 - 2)}$

$=\sf{(3(√(5) - √(2)))/(3)}$

$=\sf{\frac{\\ot{3}(√(5) - √(2))}{\\ot{3}}}$

$\blue{\boxed{\underline{\rm{\therefore\:(3)/(√(5) + √(2)) = √(5) - √(2)}}}}$

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