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When G(2,-6) is reflected in the line y = -2, the image is located at G |

User Faoxis
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1 Answer

4 votes

Answer:

The point (2, -6) is four below the line y= -2

The reflection will be four below the line y=-2.

Since y=-2 is a horizontal line, the reflection will be vertical,

so (2,-6) will reflect down 6 spaces vertically. -6 + (4*2) = (-6 + 8) = 2 therefore when we establish 4 below the line we just apply * 2 as a double as its across the line each side of the line to find that below the line = 4 = 4*2 and add it to -6

(2,-6) reflected over y=-2 reflects to (2, 2 )

Explanation:

User Levent Ozbek
by
4.8k points
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