Question

A second 0.69 bullfrog is on a log tilted 26 degrees above horizontal. How large is the normal force of the log on this bullfrog?

Answer 1

Below

Step-by-step explanation:

To find the normal force of the frog on the inclined plane we can use this formula :

`Fn = mgCos\alpha`

`Fn = (0.69kg)(9.8)Cos(26) \\ = 6.762 Cos(26) \\ = 6.07764 N \\ = 6.08 N`

Hope this helps!