128k views
3 votes
10. Write an equation in slope-

intercept form for the line that
passes through (6, 5) and is parallel
to the line x + 3y = 9.

User Brazeredge
by
5.1k points

2 Answers

7 votes

Answer:

y = -x + 11 or y + x = 11

Explanation:

x + 3y = 9

3y = -x + 9 slope = -1 .

The slope of parallel lines have the same slope.

Now let m = -1 and use point (6, 5) into the slope intercept form and solve for "b".

y = mx + b

5 = -1(6) + b

5 = -6 + b

11 = b

Next write you equation using slope (m) = -1 and b = 11

y = -1x +11 or y = -x +11

In standard form the equation is y + x = 11

User Tim Molendijk
by
5.4k points
2 votes

9514 1404 393

Answer:

y = -1/3x +7

Explanation:

The standard form equation can be found by using the given point values in the given equation to find the new constant.

x +3y = (6) +3(5) = 21

Solving for y puts this equation into slope-intercept form.

3y = -x +21 . . . . . . . subtract x

y = -1/3x +7 . . . . . . divide by 3. This is slope-intercept form

10. Write an equation in slope- intercept form for the line that passes through (6, 5) and-example-1
User Don Bottstein
by
5.3k points
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