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Could someone pls help me with this question

Could someone pls help me with this question-example-1
User Rarw
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1 Answer

5 votes

Answer:

II and III

Explanation:

Parallel lines have the same gradient, they will have the same coefficient in front of x

II: 2x + 3y = 6 needs to be rearranged to 3y = -2x + 6 and then y = -2/3x + 2: the gradient is -2/3

III: y - 8 = -2/3(x - 3) needs to expanded so y - 8 = -2/3x + 2 and then y = -2/3x + 10: again, the gradient is -2/3

The two lines are parallel because both gradients are -2/3

Hope this helps!

User Andrew Robinson
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