Answer:
Approach for first problem:
Number the bins and for i=1,2,3,4,5i=1,2,3,4,5 let BiBi denote the event that bin ii has precisely 33 balls in it.
Then to be found is:
P(⋃i=15Bi)P(⋃i=15Bi)
Applying inclusion/exclusion and symmetry we find that:
P(⋃i=15Bi)=5P(B1)−10P(B1∩B2)P(⋃i=15Bi)=5P(B1)−10P(B1∩B2)
How to find P(B1∪B2)P(B1∪B2)?
You do not need to find P(B1∪B2)P(B1∪B2)