Express (w+7)(w-2) =0 in standard form

asked Jul 10, 2022 185k views

2 votes

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5 votes

Answer:

${w}^(2) + 5w - 14= 0$

Explanation:

$(w + 7)(w - 2) = 0 \\ w(w - 2) + 7(w - 2) = 0 \\ {w}^(2) - 2w + 7w - 14 = 0 \\ {w}^(2) + 5w - 14= 0$

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3 votes

(w + 7)(w - 2)

w(w - 2) + 7(w - 2)

${w}^(2) - 2w + 7w - 14$

${w}^(2) + 5w - 14$

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