Question

The perimeter of a regular pentagon is 4 1/7

cm. Find the length of its each side​

Answer 1

29/35 cm for each of the 5 sides

Explanation:

The perimeter is the length of all the sides added together. A pentagon has 5 sides. So you'd need to divide 4 1/7 by 5.

It might be easier to divide 4 by 5 and then divide 1/7 by 5 then add the two numbers together.

4/5 = 0.80 or 8/10

1/7 divided by 5 is written as (1/7) / (5/1)

When you divide a fraction by a fraction, you flip the fraction in the denominator over and multiply the new fractions.

So (1/7) / (5/1) turns into 1/7 x 1/5 = 1 / 35

Adding 8/10 + 1/35, you first need to find the common denominator which would be 70.

8/10 would turn into 56/70

1/35 would turn into 2/70

Add them together now and you get 58 / 70. This can be reduced down to

29 / 35.

Answer 2

Before doing the question let's recall that their are two types of shapes mostly , irregular and regular . Regular shapes have all their sides equal while irregular doesn't have. And here The given shape is pentagon so it will have 5 sides . Also , it's perimeter is given i.e sum of it's all sides , If we assume it's one side to be s then perimeter will be (s+s+s+s+s) more conveniently 5s . Now , heading to our question ,

`{:\implies \quad \sf 5s=4(1)/(7)}`

`{:\implies \quad \sf 5s=(4* 7+1)/(7)}`

`{:\implies \quad \sf 5s=(28+1)/(7)}`

`{:\implies \quad \sf 5s=(29)/(7)}`

`{:\implies \quad \sf s=(29)/(7* 5)}`

`{:\implies \quad \bf \therefore \quad \underline{\underline{Each\:\: Side=(29)/(35)\:\: cm}}}`