Question

Hunter has a quarters and y dimes, having at least 18 coins worth at most

combined. A minimum of 4 of the coins are quarters and a minimum of 12
coins are dimes. Solve this system of inequalities graphically and determint
possible solution.

Answer 1

Answer:The number of nickles is 6

The number of dims is 12 .

Explanation:

Given as :

Sum of total number of dims and nickels coins = 18

The value of total combination = $1.50

Let The total number of dims = d

Let The total number of nickels = n

1 nickles = $0.05

1 dims = $0.1

According to question

Total number of dims and nickels coins = number of dims + number of nickels

Or, d + n = 18 .........1

And

$0.1 ×d + $0.05 ×n = $1.50

Or, 0.1 d + 0.05 n = 1.50 .........2

Now, Solving eq 1 an eq 2

0.1 × (d + n) - (0.1 d + 0.05 n) = 0.1 × 18 - 1.50

Or, (0.1 d - 0.1 d) + (0.1 n - 0.05 n) = 1.8 - 1.50

Or, 0 + 0.05 n = 0.3

Or, 0.05 n = 0.3

∴ n =

i.e n = 6

So, The number of nickles = n = 6

Put the value of n int eq 1

∵ d + n = 18

Or, d = 18 - n

Or, d = 18 - 6

i.e d = 12

So, The number of dims = d = 12

Hence, The number of nickles is 6 and the number of dims is 12 .

Explanation: