Question

Need an answer in Meters

Answer 1

• let's first get time

`{ \rm{s = ut + (1)/(2)g {t}^(2) }} \\ \\ { \rm{78.4 = 30t + 5 {t}^(2) }} \\ \\ { \rm{ {t}^(2) + 6t - 15.68 = 0}} \\ \\ { \rm{time \approx \: 2 \: seconds}}`

• let's find horizontal displacement

`{ \rm{s = ut + (1)/(2)g {t}^(2) }} \\ \\ { \rm{s = (30 * 2) * ( (1)/(2) * 0 * {2}^(2)) }} \\ \\ { \rm{displacement = 60 \: meters}}`

• g is acceleration due to gravity [ vertically: g is 10 m/s². horizontally: g is 0 ]