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T (x) = 5x^2- 3x+4, what is the value t (-3)?

User Vasis
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1 Answer

1 vote
1 vote
the answer is t(-3) = 58

Step-by-step explanation:
t(x) = 5x^2 -3x +4
t(-3) = 5(-3)^2 -3(-3) +4
t(-3) = 5(9) -3(-3) +4
t(-3) = 45 + 9 + 4
t(-3) = 58
User Khany
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