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Lim┬(x→1)⁡〖(1-√x)/(x^2-1)〗
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Lim┬(x→1)⁡〖(1-√x)/(x^2-1)〗

User Vajda
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2 Answers

7 votes
Wow very good answer
User EnggPS
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2 votes

Answer:

- 1/4

Explanation:


(1-√(x) )/(x^(2)-1 ) = ((1-√(x))*(1+√(x) ) )/((x+1)(x-1)(1+√(x) )) \\= (1-x)/(-(1-x)(x+1)(1+√(x) )) \\= - (1)/((x+1)(1+√(x) )) \\ \lim_(->1) - (1)/((x+1)(1+√(x) )) \\ = -(1)/((1+1)(1+√(1)) ) = - 1/4

User Venkata Krishna
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