Find the value ofnp for which the equation (7P+1)X^2+(5P-1)X+P=1

asked Apr 14, 2023 213k views

8 votes

Find the value ofnp for which the equation
(7P+1)X^2+(5P-1)X+P=1

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4 votes

Answer:

(7P+1)X^2+(5P-1)X+P=1. (7P+1)X^2+(5P-1)X+P-1=0

The quadratic will have equal roots it its discriminant = 0

Mayasky answered Apr 19, 2023

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