Answer:
if y=x^2 the x and y chart would be as follows
x y
1 1
2 4
3 9
x 12
4 16
5 25
This shows that the x which would produce twelve is between three and 4 and thus not a perfect square
9<12<15 thus 3<x<4
12 is not a perfect square because the square of 3 is 9 and the square of 4 is 16, and since 12 lies between 3 and 4, we know that the number that would be squared to produce twelve must be a decimal between 3 and 4.
Explanation:
A perfect square is a number that can be produced from squaring a counting number (...-3,-2,-1,0,1,2,3...)
This means that determining a perfect square comes down to knowing the squares of 1-10 so that you can create a table and determine where the number lies or between what numbers it would occur. If it is a perfect square it will already be on the table with little to no analysis necessary.