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A bag of M&M’s has 7 red, 2 green, 3 blue, and 8 yellow M&M’s. What is the probability of randomly picking: (Round to 4 decimal places)

A bag of M&M’s has 7 red, 2 green, 3 blue, and 8 yellow M&M’s. What is the-example-1
User Selecsosi
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1 Answer

6 votes

Answer:

Y = 40%

R or G = 25%

O = 0%

Explanation:

Total M&M's = 7+2+3+8 = 20

PY = 8/20 = .4 or 40%

P(R or G) = (2+3)/20 = 5/20 = .25 = 25%

PO = 0/20 = 0%

User Vinuthan
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